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13x-21x^2+23=0
a = -21; b = 13; c = +23;
Δ = b2-4ac
Δ = 132-4·(-21)·23
Δ = 2101
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{2101}}{2*-21}=\frac{-13-\sqrt{2101}}{-42} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{2101}}{2*-21}=\frac{-13+\sqrt{2101}}{-42} $
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